$-x^2+8x-7$
$5-x\le-1$
$y'\:=\:-y\:-\:2x,\:y\:\left(0\right)\:=\:1$
$\int6x^5\left(x^6-4\right)dx$
$\frac{8x^{-3}.3x^2}{6x^{-4}}\:$
$\left(3x^{a+3}-7y^{3a-7}\right)^2$
$\frac{x^5-13x^4-120x+83}{x+3}$
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