$\lim_{x\to\infty}\left(\frac{lnx^3}{x^3}\right)$
$16x^4-9y^2$
$\frac{dy}{dx}=\frac{2y}{3x}$
$\frac{5-9x}{3}$
$2x^2-6x-24=0$
$\left(10-9+6+8\right)-\left(-2+6-19+3\right)$
$6x+8-4x$
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