$-x^3+2x^2+5x+1-3x^2+2$
$12y^2-7y-12$
$4-\left(-7+4-5\right)+\left(-5+1\right)$
$3x=y$
$-3<x-10$
$\left(\frac{2}{5}x\:+\:\frac{1}{3}y\right)^2$
$\frac{x^4}{x^{-2}}$
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