$-\left(\frac{16}{-8}\right)+6-15$
$x^4-4x^3-17x^2+60x$
$\left(5^3\right)^{15}$
$\lim_{x\to0}\left(\frac{2x^2+6x}{x}\right)$
$\lim_{x\to\infty}\left(\frac{1}{\left(log\left(n\right)\right)^3}\right)$
$9f+-9f$
$9-\left(-32\right)-29$
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