$\frac{3b^3d^2}{6bd^5}^2$

$\tan\left(\sin^2\left(-\frac{\sqrt{3}}{2}\right)\right)$

$f\left(x\right)=x^2-4x+3$

$\int_1^x\left(x-2\right)ydx$

$10x^5-2x^4-8x^3$

$\frac{\left(x^3+7x^2+8x-16\right)}{x+4}$

$\lim_{x\to\frac{\pi}{4}}\left(\frac{7tan\left(x\right)-7cot\left(x\right)}{x-\frac{\pi}{4}}\right)$