$-3.\:\left(-5+10\right)\:-\:\left(-1\:-\:16:\:8\right)$
$\left(2t-3\right)^2$
$( x ^ { 2 } + y ^ { 2 } ) ^ { 5 }$
$\left(3+4y^2\right)^2$
$\int4sec^3xtanxdx$
$-2-\left(-6+9\right)-\left(9-12\right)$
$\frac{2^2+\left(-4\right)^2}{3^2-2^2}$
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