$\frac{3m^4n^3}{6m^3n^4}$
$xy'-2y=6x^4$
$\int x\left(x^2-3+c\right)dx$
$f\left(x\right)=\frac{\left(x^2+2x-8\right)}{x-2}$
$\left(\frac{3x}{2}-\frac{y}{3}\right)$
$3x^2+5=18x$
$1-7+2$
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