$\left(2x^4+5x^3\right)^2$
$-9\left(-w^3+3-3y^2\right)$
$y=\sqrt[4]{\frac{\left(4x+1\right)\left(x+4\right)^2}{\left(x^3+5\right)\left(x+7\right)}}$
$3x+7>1$
$19-4x-3\left(6-24x\right)$
$\sqrt{9x^2y^6}$
$\left(x^6+8\right)\left(x^6+5\right)$
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