$x-\frac{7}{x+4}=2$
$-8+4-2\cdot3$
$8m^3-27y^3$
$-\left(7-2\right)-\left(-5+7\right)+\left(14-3+12-3\right)$
$\left(x^2-y^2\right)dy=\left(xy\right)dx$
$x-26<14$
$3x-y-5=0$
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