$x-4+3x-2$
$5+\left(-3\right)-\left(-2\right)+\left(4+6\right)-\left|3-\left(6-4\right)\right|$
$x^2-20x+19=0$
$\sqrt[3]{\frac{1000}{125}}$
$\left(8x+2\right)\left(6x-2\right)$
$\frac{x^5-7x^4+6x^2-8x+4}{x+2}$
$x^2+2\ge0$
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