$\frac{\tan\left(x\right)^2}{\sec\left(x\right)+1}$
$\left(3x^2\right)+\left(2y\right)^2$
$\frac{d}{dx}\left(x^2y^2-\frac{x^3}{y}+y^2=0\right)$
$9x^2-15x$
$4x^2+8x^3-9x^2+2x$
$\lim_{x\to8}\frac{\left(x^2-2x+48\right)}{x-8}$
$\left(3a+x^3\right)^3$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!