$\left(3-2x\right)<5$
$\left(5x-4^2\right)$
$16y^2-4$
$x^4-x^3-6x^2$
$49a^2-1$
$\int_1^{\infty}\left(\frac{2}{3x-1}\right)dx$
$\int\sqrt[3]{4-5x^2}\left(-10x\right)dx$
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