$\left(2x^3+9x\right)^2$
$\left(7x-.5\right)\left(7x+.5\right)$
$-6-28-22-14-15+19-38$
$\frac{12^{10}\cdot18^{5}\cdot16^{-1}}{8^{5}\cdot54^{6}}$
$\tan^2a-\sec^2a$
$\sqrt{\left(\frac{x-5}{x^8+3}\right)}$
$3x+2y+5=0$
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