$cos^2x\:+\:2\:cos\:x\:+\:1\:=\:0$
$\frac{x^2+3x+2}{-3x^2+19x-6}$
$\frac{\left(\frac{1}{cosx}\right)^4-tanx^4-1}{2cotx^2}$
$\lim_{x\to0}\left(\frac{1-6x}{x}\right)$
$\frac{x+2}{2}-\frac{2x-1}{6}\ge\frac{2x-1}{3}+\frac{x-3}{12}$
$9x-9-8x-32$
$6^3-15\left(6\right)^2+72\left(6\right)+8$
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