$6\cos^2\left(x\right)+\cos\left(x\right)-2=0$
$\frac{xy^3}{4xy}$
$6x^2y^2-12x^2y^2+x^2y^2-4x^2y^2$
$\left(x+5\right)^2-\left(x-8\right)^2$
$12x^{-6}y$
$0^4$
$23\:x^2\:+8\:=\:27\:x^2-\:8$
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