$6.4\:-\:\left(-2\right)\:=\:$
$\lim_{x\to1}\left(\frac{e^{x^2}-e}{3x-3}\right)$
$x^2=27-6x$
$5x-3x^2+1$
$\frac{\sqrt{3.001+6}-3}{3.001-3}$
$\frac{x}{x-1}\ge\frac{1}{x-1}$
$\left(m^{2x}\right)^2$
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