$-2\frac{1}{2}-4\frac{3}{4}$
$x^2+7x-8=0$
$4-2^2-\left(-1\right)^3+\left(3-\left(5-3^2\right)\right)$
$-6+x=-1$
$-6\left(x+7\right)=-4x-2$
$\sqrt{-121}$
$6\:+\:\sqrt{x+2}=\:\sqrt{3x+10}$
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