$x^4+4x^{-1}+\frac{4}{x^5}$
$\left(2x^3+3x\right)^2$
$\left(x+21\right)^5$
$\sqrt[3]{125^9}$
$x^2+12x+8$
$\left(-1\right)\left(0\right)\left(6\right)+\left(5\right)\left(-3\right)\left(10\right)+\left(4\right)\left(2\right)\left(6\right)-\left(4\right)\left(0\right)\left(10\right)-\left(-1\right)\left(-3\right)\left(7\right)-\left(-6\right)\left(2\right)\left(4\right)$
$\left(g-u\right)^2$
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