$2.38+3$
$x^2+2x=5$
$\int\frac{y}{\left(y^2-16\right)}dx$
$5\cdot\left(2-6\right)+2\cdot\left(19-7\right)$
$x^2-4x+4\le0$
$\tan^2\left(x\right)+1=\frac{1}{5}$
$\frac{\sqrt{3}+\sqrt{2}}{\sqrt{2}}e^{1}$
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