$x^2-3x+4>0$
$-9\left[9+x\right]=0$
$1-2\cdot\sin\left(x\right)^2-\sin\left(x\right)=0$
$x^2-64=0$
$x^2+6=5x$
$\lim_{x\to0}\left(\frac{a^x+b^x+c^x}{3}\right)\frac{1}{x}$
$\sqrt[3]{2+6}-2$
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