$\frac{x^3+6x^2+5x+1}{x-1}$
$\frac{senx+cosx}{cosx}=1+cotgx$
$\sqrt{10+\sqrt{32+\sqrt{13+\sqrt{x}}}=4}$
$2^2-\left|-12+\left(-5\right)\right|$
$\frac{\left(-18\right)}{-\left(-6\right)}$
$41.5+31$
$\frac{dy}{dx}=\frac{1-sinx\:\cdot\:y}{cosx}$
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