$2\left(x\right)+2\left(3x\right)$
$\lim_{x\to\infty}\left(\frac{e^x}{2x^2}\right)$
$\lim_{x\to5}-\frac{1}{\left(x-5\right)}$
$\sqrt[2]{x-6}=3$
$\left(-12\right)=\:1$
$\frac{dy}{dx}=\frac{x^3-cos\left(x\right)}{4y}$
$\left(4y+9x\right).dx+\left(3y+8x\right).dy=0$
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