$\lim_{x\to0}\frac{\left(1-\cos\left(2x\right)+\tan^2\left(2x\right)\right)}{x\sin\left(3x\right)}$
$2x+2=2\left(3x-1\right)$
$4a^4-12a^2+9$
$\ln\left(x+1\right)^2=2$
$x^2-\frac{1664}{81}-\frac{86528}{81}$
$3\le\frac{2x+4}{x-1}$
$-5\left(3b+4\right)-6\left(3+6b\right)$
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