$\left(\frac{2x}{3}-\frac{3y}{4}\right)^3$
$\left(x^3-b\right)^3$
$\left(2x+5\right)\left(x^2-9\right)$
$x^{-3}-y^{-3}$
$\sqrt{4a}$
$-10\left(6\right)-7$
$\lim_{x\to\infty}\left(\sqrt[x]{3^{1+3x}}\right)$
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