$x-3y\cdot3x+4y$
$\int\left(3xe^{\left(5-6x^2\right)}\right)dx$
$\frac{x^2-4}{x^3-10}$
$\int\frac{\left(x^2+x-10\right)}{2x^3-3x^2+8x-12}dx$
$2x^2-x-3^2$
$\left(11-\frac{1}{y}\right)\left(-11-\frac{1}{y}\right)$
$-12x-48$
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