$\frac{-3x^4\:+6x^3\:-12x^2}{3x^2}$
$\frac{dy}{dx}.y=-x$
$\left(105\right)\left(-7\right)$
$3+1-6+4$
$63\left(\frac{5}{7}\right)$
$\frac{d}{dx}\left(x^3+\frac{x}{y}-y^3=0\right)$
$\frac{dy}{dx}=\frac{1}{4}y\left(1-y\right)$
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