$\frac{x^3-5x^1+3}{x-2}$
$9^2+4m^2$
$\left(2\right)\left(-2\right)\left(-2\right)\left(3\right)$
$-27=-8$
$\lim_{x\to\infty}\left(\left(x^3-5x^2\right)^{\frac{1}{3}}-x\right)$
$\left|12\cdot\left(-6\right)\right|$
$16a^2+10a$
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