$x^2-42x-441$
$\lim_{x\to\infty}\:\frac{1^{x+1}-1}{1^x+1}$
$-2\left(0\right)+1$
$\left(4x^2-1\right)^4$
$\frac{x^2-3x-7}{x-5}$
$\int\left(\frac{1}{f}\right)dx$
$\frac{\left(x-1\right)}{3}+\frac{1}{6}\le\frac{x}{2}-3$
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