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The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.
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$\left(x-2\right)^2>x^2-4+8$
Learn how to solve inequalities problems step by step online. Solve the inequality (x-2)^2>(x+2)(x-2)+8. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Subtract the values 8 and -4. Expand \left(x-2\right)^2. Grouping terms.