$x-8=\left(-a-b\right)x+\left(2a+3b\right)$
$\int\left(\frac{\left(2-4x\right)}{\left(x+2\right)\left(x-3\right)}\right)dx$
$a+b=6$
$\int cos\left(4x\right)^{-6}dx$
$y'=\frac{2x}{y^3}$
$-\sqrt{-9}-3\sqrt{-9}$
$\int_{0}^{5}e^{x}dx$
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