$\lim_{x\to\infty}\left(\frac{20x}{20x+2}\right)^{3x}$
$\frac{-a^3b^4}{6a^3b^2}$
$x-1=x^2-2x+1$
$-2\:\left(\:10+\:\left(-8\right)\:\right)$
$25x^2-30x+8$
$\frac{x}{2}=\frac{7}{x}-\frac{5}{2}$
$\int15x^4dx$
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