$\frac{s}{6}+12\ge9$
$\left(\frac{1}{2}a-\frac{1}{3}b\right)^2$
$x^2-x+4<0$
$n^2+3n=10$
$7.\:4\:-\left(-18\right)$
$\frac{d}{dz}\left(\frac{\sin\left(3z+z^2\right)}{\left(6-z^4\right)^3}\right)$
$2+6-9-1+4-7-2+8$
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