$x^{''}+4x^'+4x=0$
$7^0\cdot7^3$
$e^{-3x}=\left(e^7\right)^{x+10}$
$x^2-\frac{1}{3}=0$
$\left(\frac{2}{3}x-\:\frac{1}{2}\right)^3$
$\left(\left(x^2\right)-\left(y^2\right)\right)dx+2xydy$
$\left(6xg^2+5m^4\right)^2$
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