$\int\sqrt{x}\sqrt{1+\frac{1}{4x}}dx$
$l=1+\frac{1}{1+l}$
$\int x^33^xdx$
$\frac{8\left(\sqrt{3}\sqrt{x}+24\right)}{3},\:x=7$
$196x^6-144y^{14}$
$a^3\left(m-3\right)+n\left(m-3\right)$
$\frac{dy}{dx}=\frac{xe^{4x+y^5}}{y^4}$
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