$-440^2$
$\int_2^4\left(2x-3\right)\left(x^2+3x+5\right)dx$
$-1-\left(8\right)$
$\frac{dy}{dx}=\frac{2sin\left(x\right)}{1-y}$
$\frac{d}{dx}8x\:cosy=y$
$\lim_{x\to\infty}\left(x^2-2x+5\right)$
$y^2+4y-4$
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