$\frac{d}{dx}\left(x^2+-3\ln\left(y\right)+y^2=16\right)$
$\ln\left(\sqrt{4x^2+3x}\right)$
$9x^3+8^2-5x+15$
$\left(2xy\right)dy\:=\:\left(4x^2+3y^2\right)dx$
$x^3-5x^2+3x+14\:+\:x-3$
$\frac{\sqrt{2}}{0.5}$
$\sqrt[6]{\frac{1}{m^2}}\cdot\:\sqrt{\frac{1}{m}}$
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