$\frac{x}{\left(x^2+3\right)^{\frac{1}{2}}}$
$-x^3-2x^2+1$
$\frac{\left(3x+1\right)}{x+2}>2$
$3x^4=243$
$\lim_{x\to4}\left(\frac{10x^2+50x}{x^2-25}\right)$
$+4\left(-6\right)-\left(-3\right)+5-9$
$x^2-11x=1$
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