$\frac{8x^3y^5}{2xy^2}$
$w-3=-12$
$\lim_{x\to0}\left(\frac{3-3\cos\left(x\right)}{sin\left(6x\right)}\right)$
$\frac{x}{3}+1=7$
$\frac{6x-1}{6}\le17x$
$6.81\:x\:10^5$
$5\left(-2\right)-2\left(7\right)+3\left(-3\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!