$\int\left(3x-1\right)^4\cdot2xdx$
$\int12x^2\left(x^3-7\right)^5dx$
$3x^2+x=10$
$x^2-\:x+169$
$5x-10<2x-10$
$\left(x-4\right)\left(x+8\right)=0$
$\int x\left(\frac{7}{x+5}-\frac{3}{2-x}\right)dx$
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