$\ln\frac{x}{8}$
$\frac{dy}{e^{-2x}dx}=4y^2\left(4x-1\right)$
$21\:-\:12\:+\:2\:-\:|\:5\:|\:-\:34\:+\:|-12|$
$81y^4-16z^4$
$\frac{2x^{-2}y^4}{4x^4y^3}$
$\frac{2x^3y^8}{12xy^2}$
$\frac{dy}{dx}=x^2y\:y\left(1\right)=e$
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