$\frac{y}{12}+3=-7$
$h\left(z\right)=\frac{4z}{z^3}$
$\frac{x^3y^3z^3+1}{xyz+1}$
$\left(5x+4y\right)\left(5x+2y\right)$
$x^2-7x+\frac{7}{2}^2$
$q2\:+\:20q\:+100$
$x^2+3\le-5x-3$
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