$\lim_{x\to0}\left(\frac{\left(x^2+1\right)}{\left(x^3\right)}\right)$
$x^2+\frac{8}{7}+7$
$\left(-5\right)\left(-3\right)\left(-2\right)$
$\frac{0.5}{12}\left(12.5665\right)$
$\int-\frac{2}{5x+1}dx$
$16f^2\:+\:50f\:+\:25$
$1\frac{-x-5}{9}<9+x$
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