$\frac{\left(x^3+\left(1-n^2\right)x+n+5\right)}{x+n}$
$5+2^{x+6}=9$
$2^2\cdot5^2$
$3x+2\ge x$
$2\cdot\left(x-1\right)\ge8$
$y=\sqrt[4]{\left(x+1\right)^3}\sqrt{\left(x^2-x\right)}$
$\left(2a^2b^3+3a^4b^2\right)^3$
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