$4a\left(3a^2+5a-8\right)$
$12x-14=-2x^2$
$-6\cdot12-13$
$0=2\tan\left(x\right)\cos\left(x\right)+\sqrt{3}\tan\left(x\right)$
$3x-21<6$
$8\left(2\right)\left(3\right)\frac{3}{2}$
$\left(x-6\right)dx=\left(y+3\right)dy$
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