$\lim_{n\to\infty}\left(\frac{n^5}{2^n}\right)$
$-1^4$
$a+1\:\cdot\:a+2$
$\frac{sec^2\left(x\right)-tan^2\left(x\right)}{csc\:\left(x\right)}=sin\left(x\right)$
$7\:x\:2\:-\:20\:x\:-\:3$
$\int\frac{\sqrt{t}}{t+1}dt$
$3a^4\cdot a^2$
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