$x+\frac{1}{5}\left(x+2\right)>1$
$6x+8\:\:6x-8$
$\frac{dy}{dx}=3x^2-8x+5$
$-21\:-\:\left[\left(-19\right)\:+\:31\:-\:29\:-\:\left(-12\right)\right]$
$2x\:+8\:=\:x\:+\:15$
$34.2+42.47+5.64+2.222$
$-9x-6\:x\:2$
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