$x^2-20x=5$
$\left(6-2a\right)^3$
$x+1>2x+4$
$\left(\frac{1}{4}x+\frac{2}{3}x\right)^2$
$\left(y-bx-c\right)^2$
$\left(ax+10\right)^2$
$\lim_{x\to\infty}\left(\frac{x^2-4}{x+4}\right)$
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