$x^2+10x+9=x-1$
$f\left(x\right)=3x\left(x+1\right)\left(x-4\right)^2$
$\sin y=\cos2x$
$y'-3y=-x$
$\frac{2\cdot\left(\frac{x}{1}\right)^3}{x^2}$
$10x\:+\:41\:\le\:9x\:-10$
$\int e^x\cdot2x$
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