$\left(2x^2-3y^6\right)^2$
$-x^2-4x+13$
$\frac{dy}{dx}=\frac{x^2+t\sqrt{t^2+x^2}}{tx}$
$c^2+c+c$
$xdy=\left(y-xy\right)dx$
$\left(0.99\right)^2$
$\frac{8x^2-4x-7}{x^2}$
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