$\frac{a^2}{4}-\frac{b}{16}$
$\int\frac{x^3}{\sqrt{9x^4+6x^2-1}}dx$
$\left(a^2+b^2+c^2\right)^2\left(a+b+c\right)\left(a^8+b^8+c^8\right)$
$x^2-6x+1\le2x^2-4x+2$
$\frac{3.6742}{9}$
$b^2+14b+33$
$4\left(5f\right)$
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